Chemistry, 24.08.2019 12:00 lilbrown6369

8which quantity is equal to one mole of au? (1) the atomic mass in grams
(2) the atomic number in grams
(3) the mass of neutrons in grams
(4) the number of neutrons in grams

Answers: 2

Show answers

Answers

Answer from: seanjung1128

Answer is (1) the atomic mass in grams since One mole of any element is equal to the atomic mass in grams.

Answer from: lcaulkett27

option (1) the atomic mass in grams.

Explanation:

1) The atomic mass is the mass in grams of one mole of atoms.

2) Hence, it is always the atomic mass of an element equal to the mass of one mole of atoms of such element. Therefore, the atomic mass of Au is the mass of one moles of atoms of Au.

3) Here are some examples:

i) Atomic mass of gold: 196.67 g/atoms, means that 196.97 grams of Au is one mole of Au.

ii) Atomic mass of hydrogen: 1.008 g/mol, means that 1.008 grams of H is one mole of H.

iii) Atomic mass of oxygen: 15.999 g/mol, means that 15.999 grams of O is one mole of O.

iv) Atomic mass of lead: 207.2 g/mol, means that 207.2 grams of Pb is one mole of Pb.

Now you see it, the atomic mass in grams of an element is equal to one mole of the element.

Answer from: Quest

answer7,570,82356 cubic centimeters;

Answer from: Quest

remember that hf is only the energy of one photon. not two. not three. one. 1) 5.12 * 10^3 photons find the energy of one photon, then determine how many photons are needed to reach the sensitivity. e = hf = (6.626 * 10^-34 js)(5.95 * 10^19 hz) = 3.94247 * 10^-14 j per photon (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons round to three sig figs. 2) 5.77 * 10^-17 j energy of pulse = energy per photon * number of photons = hfn = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250) = 5.774559 * 10^-17 j round to three sig figs. 3) 4.07 * 10^8 kj/mol 10^12 pm = 1 m c = fλ f = c/λ e = hf = hc/λ = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol) = 40702571.4 kj/mol round to three sig figs. 4) 9.94 * 10^-1 m e = hc/λ λ = hc / e = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j) = 0.9939 m round to three sig figs. 5) 9.06 * 10^3 photons energy of pulse = energy per photon * number of photons number of photons = energy of pulse / energy per photon = energy of pulse / (hf) = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)] = 9055.23695 photons round to three sig figs. 6) 2.78 * 10^-15 j this is problem 1, except in reverse. sensitivity = minumum number of photons * energy per photon = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz) = 2.78070758 × 10^-15 j round to three sig figs.

Another question on Chemistry

Chemistry, 21.06.2019 22:00

Fission of uranium-235 products energy and a. isotopes of smaller elements b. isotopes of larger elements c. lighter isotopes of uranium d. heavier isotopes of uranium

Answers: 3

Answer

Chemistry, 22.06.2019 05:30

Which of the following two events occur to create a sea breeze? select all that apply. warm air rises on the ocean and moves toward the land to cool warm air rises on land and moves toward the ocean to cool cool air moves from the ocean to be warmed by the land cool air moves from the land to be warmed by the ocean

Answers: 3

Answer

Chemistry, 22.06.2019 12:30

The bond energy for the van der waals bond between two helium atoms is 7.9×10−4ev. assuming that the average kinetic energy of a helium atom is (3/2)kbt, at what temperature is the average kinetic energy equal to the bond energy between two helium atoms

Answers: 1

Answer

Chemistry, 22.06.2019 13:00

Tell me the iupac names of the following alcohols:

Answers: 2

Answer

You know the right answer?

8which quantity is equal to one mole of au? (1) the atomic mass in grams
(2) the atomic number...

Questions