An analysis of a 4.2-gram sample of a compound is found to contain 54.76 percent sodium (na) and 45.24 percent fluorine (f). determine the empirical formula of the compound

NaF

Explanation:

If the 54.76% of the sample is sodium and 45.24% is fluorine. Mass of each atom is:

Na: 4.2g × 0.5476 = 2.3g

F: 4.2g × 0.4524 = 1.9g

In moles:

Na: 2.3g × (1mol / 22.99g) = 0.1 moles

F: 1.9g × (1mol / 19) = 0.1 moles

As empirical formula is defined as the simplest whole-number ratio of atoms in a compound, the ratio of Na:F is:

0.1 / 0.1 = 1. Thus, empirical formula is:

NaF

there is none because earth is stationary and flat.

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.