Consider the reaction ch3oh(l)→ch4(g)+1/2o2(g). part a calculate δrh∘298.

Explanation:

Hello,

In this case, the proper way to compute the enthalpy of reaction is as shown below:

Wherein all the enthalpy changes are referred to the formation enthalpy which are subsequently replaced for each compound at its corresponding phase as follows:

Best regards.

thats a little if u want the answer just look it up on google thats what i do haha : )