Calculate the boiling point of a 4.5 m solution of na2so4 in water (assume 100% dissociation, kb (h2o) = 0.52 â°c/m)

In order to determine the change in boiling point, we use the formula:
ΔT = Kb * m * i

Where i is the van't Hoff factor. This factor is found by checking the number of ions formed when the solute is dissolved. This is:

Na₂SO₄ + water ↔ 2Na⁺ + SO₄⁻²

The number of ions formed is 3, so i = 3

ΔT = 0.52 * 4.5 * 3
ΔT = 7.02

The new boiling point is calculated using:
T = T(normal) + ΔT
T = 100 + 7.02

The new boiling point is 107.2 °C

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The reaction 2kalsi3o8 + 2(h+ + hco3-) + h2o  →  al2si2o5(oh)4 + 2k+ + 2hco3- + 4sio2 shows that feldspar kalsi3o8 is chemically altered by hydrolysis to form chalky-looking clay mineral kaolinite al2si2o5(oh)4. the chemical breakdown of potassium feldspar due to exposure to acidic water results to the mineral binding with the water molecule to become kaolinite with silica and potassium and bicarbonate ions in solution.