A0.100-g sample of your favorite candy is burned in a calorimeter that contains 1.00 kg of water initially at 21.0 ∘c. after the candy is burned, the water temperature is 34.5 ∘c. how many calories are there per gram of your candy?

565.245kJ
To answer this question, you need to know how much water heat capacity which was 4.187 kJ/kg K. First, we need to find the calorie absorbed by water. Since the sample is 1kg, the initial temperature is 21 ∘C and final temperature is 34.5 ∘C then the calculation would be:

Energy= (Final temp - initial temp) * heat capacity * mass
Energy = (34.5-21) ∘C * 4.187 * kJ/kg K * 1kg= 56.5245 kJ

The energy is made from 0.1 gram, then for 1 gram of energy it should be:
1 gram/ 0.1gram x 56.5245 kJ= 565.245kJ

Ifound this on google “these two compounds have a different ionic structure. caesium ion is larger in size when compared to the sodium ion. the charge gets more area to spread out evenly. so caesium chloride has a lower melting point than sodium chloride.” i hope this you for what your looking for