Air is 21% oxygen by volume. oxygen has a density of 1.31 g/l. what is the volume in liters of a room that holds enough air to contain 55kg of oxygen?

The volume of the room that can hold enough air containing 55 Kg of oxygen is 199927.29 L

We'll begin by converting 55 kg of oxygen to grams (g). This can be obtained as follow:

1 Kg = 1000 g

Therefore,

55 kg = 55 × 1000

Next, we shall determine the volume of oxygen. This can be obtained as follow:

Mass of oxygen = 55000 kg

Density of oxygen = 1.31 g/L

Cross multiply

1.31 × Volume = 55000

Divide both side by 1.31

Volume = 55000 / 1.31

Finally, we shall determine the volume of the room by calculating the volume of air. This can be obtained as follow:

Volume of oxygen = 41984.73 L

Percentage of oxygen in air = 21%

21% =

Cross multiply

0.21 × Volume of air = 41984.73

Divide both side by 0.21

Therefore, we can conclude that the volume of the room that can hold enough air containing 55 Kg of oxygen is 199927.29 L

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