How does 0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution?

0.5 m sucrose (molecular mass 342) solution compare to 0.5 m glucose (molecular mass 180) solution has a mass ratio of 2: 1

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.

Molarity shows the number of moles of solute in every 1 liter of solution.

m = Molality

n = Number of moles of solute

p = Solvent mass (gram)

The mole fraction shows the mole ratio of a substance to the mole of solution / mixture

nA + nB = 1

There are 0.5 m sucrose (molecular mass 342) solution and 0.5 m glucose (molecular mass 180)

Then the comparison of the two is from the ratio of mass (assuming the mass of the solvent is equal to 1 kg)

Sucrose (C₁₂H₂₂O₁₁) 0.5 molal then the mass:

mass = 0.5 m x 342 = 171 grams

Glucose (C₆H₁₂O₆) 0.5 molal then the mass:

mass = 0.5 m x 180 = 90 grams

So the mass ratio = 171: 90 = 1.9: 1 or we round it to 2: 1

the molality of the solution

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the difference between molarity and molality

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Keywords: molality, glucose, sucrose, mass, solvent,

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