Chemistry, 20.04.2021 18:30 korrinevbrulz2222

CUESTIONARIO EJERCICIOS DE CONVERSION SI DE UNIDADES 1. Realizar el procedimiento necesario, utilizando los factores de conversión pertinentes para
convertir 150

a

2. Realizar el procedimiento necesario, utilizando los factores de conversión pertinentes para
convertir 5000

a

3. Realizar el procedimiento necesario, utilizando los factores de conversión pertinentes para
convertir: 130
3
a

3
.
4. Realizar el procedimiento necesario, utilizando los factores de conversión pertinentes para
convertir: 155 pie3
a galones.
5. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir: 118
2
a

2
6. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir: 18

3
a

3
7. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir: 5000 x108 pm a mm.
8. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir 250 A
0
a micras. (1Ao = 1x10 -8
cm)
9. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir:2500 hectómetros a kilometros.
10. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir: 625 pm a nm
11. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir:24

a

3
12. Realizar el procedimiento necesario, utilizando los factores de conversión pertinente para
convertir 81

a
3
13. Cuánto pesan 224 cm3 de aire seco, si su densidad es de es 0, 001225 g/ cm3
.
14 . Determinar la capacidad en metros cúbicos de una caja de 0,80 m de larga,
2.5 pies de ancha y 17 pulgadas de profundidad.
15.La densidad media de la tierra es de 5,51
3
, su masa es de 5,972 X 1021Kg . Calcular
el volumen de la tierra en Km3
.
16. El etanol tiene una densidad de 0,789

. Calcular dicha densidad en libras americanas
(lb) por galón. (galón = 3, 785 litros)
17. Determinar la cantidad de litros de petróleo que hay en 80 barriles de dicha fuente de
energía, ( 1 barril = 42 galones).
18. Si el caudal de agua en un vertedero es de 15 3
. ¿Cuál es el caudal en litros por hora?;
el caudal (Q) es volumen de un líquido por unidad de tiempo.

Answers: 2

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Answers

Answer from: Quest

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'

Answer from: Quest

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Answer from: Quest

the missing options are :

(1) lower boiling point and a lower freezing point(2) lower boiling point and a higher freezing point(3) higher boiling point and a lower freezing point(4) higher boiling point and a higher freezing point

answer : the correct answer is option (3) higher boiling point and a lower freezing point

explanation :

when a non volatile solute is added to a solvent like water, it results in elevation of boiling point.

let us find the increase in boiling point of water when cacl₂ is added to water to make a solution of 1 m

step 1 : find molality of the solution

let us assume we have 1 l of solution.

$m = \frac{moles (solute)}{l ( solution)}$

$1 m = \frac{moles (cacl_{2})}{1 l }= 1 mol cacl_{2}$

let us convert this to grams of cacl₂.

molar mass of cacl2 is 111 g/mol

grams of cacl₂ = $1 mol \times \frac{111g}{mol} = 111 g cacl_{2}$

mass of solute = 111 g

assuming density of solution same as water which is 1g/ml we have ,

mass of solution = density * volume

mass of solution = $\frac{1g}{ml} \times 1000 ml = 1000 g$

mass of solution = mass of solvent + mass of solute

mass of solute = 1000g - 111g

mass of solute 889 g = 0.889 kg

the molality of the solution can be calculated as

$molality = \frac{mol (solute)}{kg ( solvent)}$

$molality = \frac{1mol}{0.889kg}$

molality = 1.12 m

step 2 : find boiling point elevation.

the elevation in boiling point is calculated as

$\bigtriangleup t_{b} = i \times k_{b} \times m$

here δtb = boiling point elevation

i = vant hoff factor which is the number of ions formed by the solute .

cacl₂ dissociates as $cacl_{2} \rightarrow ca^{2+} + 2 cl^{-}$

it forms 3 ions . therefore,

i = 3

m = molality which is 1.12 m

kb is constant for a given solvent. for water it is 0.512

$\bigtriangleup t_{b} = 3 \times 0.512 \times 1.12$

$\bigtriangleup t_{b} = 1.7$

the boiling point of water increases by 1.7 °c

step 3: find freezing point depression.

when a non volatile solute is added to water, it results in decrease in freezing point.

the formula to find freezing point depression is

$\bigtriangleup t_{f} = i \times k_{f} \times m$

kf is constant for water and its value is 1.86

$\bigtriangleup t_{f} = 3 \times 1.86 \times 1.12$

$\bigtriangleup t_{f} = 6.2$

the freezing point of water decreases by 6.2 °c

therefore we can say that, the solution will have a higher boiling point and a lower freezing point

Answer from: Quest

Answer: 1.0 × 10⁻⁵ msolution: as we know ph is given as, ph = -log [h⁺]and, [h⁺] = 10^-ph (1)putting value of ph in eq. 1, [h⁺] = 10⁻⁵ [h⁺] = 1.0 × 10⁻⁵ m

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CUESTIONARIO EJERCICIOS DE CONVERSION SI DE UNIDADES 1. Realizar el procedimiento necesario, utili...