What is the molar solubility of lead phosphate in water in moles?

Please help?!

Now, the molar solubility of lead(II) phosphate in water is said to be equal to 6.2⋅10−12mol L−1 . This means that in one liter of water, presumably at room temperature, you can only hope to dissolve 6.2⋅10−12 moles of lead(II) phosphate.

Explanation:

Hope this helps!!

hey there!

boiling point is the temperature at which the vapor pressure of the liquid equals atmospheric pressure. the vapor pressure of solvent molecules is decreased when a solute is added, so a higher temperature is required to increase the number of solvent molecules in the gas phase above the liquid.

at the freezing point, the vapor pressures of the solid and liquid are equal; a lower temperature is needed to reduce the number of solvent particles above the liquid.

hope this you

tobey