Calculate the heat needed to change 2.50 x 10 2 grams of ice at 0.0°C to steam at 100.0 °C. How much heat is removed from 60.0 g of steam at 100.0°C to change it to 60.0 g of water at 20.0 °C

Does anyone know how I would go about solving either of these problems?

? you expect us to answer this? ? this is your schoolwork, i don't think we can with this, i think it would considering being

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer