What is the potential difference across a light bulb when there is 32 A of current and 8 Ω of resistance from the filament.

force ε: the increase in potential energy per unit charge provided by the chemical reactions in the battery. And the voltage difference across the light bulb is: ∆V = I R = (0.06 A)(20 Ω) = 1.2 V ▪If we measure the voltage difference across the battery or the light bulb, we will get 1.2 V.

Explanation:

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