When 10 mol of HCl is dissolved in 5 liters of water , what is the molarity of the HCl solution? A) 2 M ( = 2 mol/L)
B)5 M (= 5 mol/L)
C)15M (= 15 mol/L)
D)50 M (= 50 mol/L)

i'm pretty sure it is letter c.) car

it is the most commonly accepted one

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally