PLS HELP A 20.8 gram piece of metal at 184.9 oC is dropped into 87.7 grams of water at 19.2 oC. The water temperature rose to 54.6 oC. Calculate the specific heat of metal in J/g oC. (round to the tenths place) (DO NOT PUT UNITS IN YOUR ANSWER.)

Assume that all of the heat lost by the metal is transferred to the water and no heat is lost to the surroundings. The specific heat of water is 4.184 J / g oC.

Explanation:

A 12.48 g sample of an unknown metal, heated to 99.0 °C was then plunged into 50.0 mL of 25.0 °C water. The temperature of the water rose to 28.1 Go to calculating final temperature when mixing two samples of water ... Problem #1: A 610. g piece of copper tubing is heated to 95.3 °C and placed in an ... The two rings are heated to 65.4 °C and dropped into 12.4 mL of water at 22.3 °C. ... Problem #4: A 5.00 g sample of aluminum (specific heat capacity = 0.89 J g¯1

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explanation:

c is the answer because when something is left after something evaporates that shows the chemical change.