A 3.0 liter tank of oxygen gas is at a pressure of 7.0 atm. What volume of oxygen (in liters) will you have if the size of the container changes, resulting in a final pressure of 2.0 atm? Make sure you enter only the numerical answer, no units. Also, the significant figure rules for this question require rounding!
Thanks.

its mg hope this

2b2t

explanation:

2b2t

pv=nrt

explanation:

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied