Consider the following system at equilibrium where Kc = 9.52×10-2 and H° = 18.8 kJ/mol at 350 K. CH4 (g) + CCl4 (g) 2 CH2Cl2 (g) The production of CH2Cl2 (g) is favored by: Indicate True (T) or False (F) for each of the following: ___ 1. increasing the temperature. ___ 2. increasing the pressure (by changing the volume). ___ 3. increasing the volume. ___ 4. removing CH2Cl2 . ___ 5. adding CCl4 .

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.