53 points and brainliest no link pls : in the Contact Process, sulfur dioxide is converted into sulfur trioxide and the following equilibrium is set up: SO2 (g) + O2 (g)--> 2 SO3 (g) ∆H = -27 kJ a) If sulfur dioxide is added to the mixture, what happens to the position of the equilibrium? b) If a catalyst is added to the mixture, what happens to the position of the equilibrium? c) if the pressure was increased in the above reaction, what happens to the position of the equilibrium? *

A0.10 m aqueous solution of sodium sulfate is a better conductor of electricity than a 0.10 m aqueous solution of sodium chloride. which of the following best explains this observation? (a) sodium sulfate is more soluble in water than sodium chloride. (b) sodium sulfate has a higher molar mass than sodium chloride. (c) to prepare a given volume of 0.10 m solution, the mass of sodium sulfate needed is more than twice the mass of sodium chloride needed. (d) more moles of ions are present in a given volume of 0.10 m sodium sulfate than in the same volume of 0.10 m sodium chloride. (e) the degree of dissociation of sodium sulfate in solution is significantly greater than that of sodium chloride.