How many moles of aluminum (Al) produced in the reaction if 30.00 grams of magnesium (Mg) was consumed. (Atomic mass for Mg =24.305 g/mol) 2AlPO4 + 3Mg rightwards arrow 2Al + Mg3(PO4)2

0.62 moles of (Al)
0.82 moles of (Al)
0.42 moles of (Al)

it should be all of them because it asks if you included all of those in your answer

explanation:

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.  

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )