What is the energy required to evaporate two moles of liquid water given the following equations? 2H2(g) + O2(g) → 2H2O(g) ∆H = -483.6 kJ

2H2(g) + O2(g) → 2H2O(l) ∆H = -571.6 kJ

a
44.0 kJ
b
88.0 kJ
c
527.6 kJ
d
1055.2 kJ

The following reaction shows the products when sulfuric acid and aluminum hydroxide react. al(oh)3 + h2so4 → al2(so4)3 + h2o the table shows the calculated amounts of reactants and products when the reaction was conducted in a laboratory. sulfuric acid aluminum hydroxide initial amount of reactant 40 g 15 g theoretical yield of water from reactant 14.69 g 10.38 g what is the approximate amount of the leftover reactant? 11.73 g of sulfuric acid 10.33 g of sulfuric acid 11.12 g of aluminum hydroxide 13.67 g of aluminum hydroxide