Use following chemical equation for the remaining questions: 2LiBr + I2 → 2LiI + Br2
** answers should be in correct number of significant digits for 2a and 2b**
2a. 174 g LiBr is equal to how many moles of LiBr?
1 mol
1.00 mol
2.00 mol
2 mol

2b. If 812 g LiBr is added to the reaction, how many liters of Br2 will be produced?
22.40 L
52.3 L
52.27 L
22.4 L

Honors Only
2c. If 22 g LiBr produces 41 g LiI and 35 g I2 produces 45 g LiI, which reactant is the limiting reactant?
LiBr
I2
LiI
Br2

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o