Pd(NO₃)₂ + NaCl ---> PdCl₂ + NaNO₃ 140 grams of lead (II) nitrate (Pd(NO₃)₂) are dissolved in water then mixed with a solution containing 75 grams of sodium chloride (NaCl). The reaction creates the precipitate, lead (II) Chloride (PdCl₂), and a solution of sodium nitrate (NaNO₃) . How many grams of lead (II) Chloride can be produced given the initial amount of lead (II) nitrate?

Stoichometry based.

All I need is the set up, but you can give answer if you want.

Please help.

hydrocarbons are organic compounds that contain only hydrogens and carbons. they can be saturated (those which contain only carbon-carbon single bonds) or unsaturated (those which contain carbon-carbon double or triple bonds) in nature. hydrocarbons can undergo several reactions like substitution, elimination etc.  

on substituting one or more hydrogen atoms in hydrocarbon it results in the formation of haloalkane. as the halogen atoms are large compared to the carbon and hydrogen atoms, due to which the molecular weight increases and the bond become polar because of presence electronegative halogen atom and results in the increase in boiling point of the haloalkane.

thus, the correct option is (b) that is the boiling point of the new compound increases on substituting a hydrogen atom with a halogen in a hydrocarbon.