1. Calculate the heat gained by the water (lost by the metal) in the calorimeter using the equation in the introduction. Metal A

Q = mc(ΔT)
Qwater = -Qmetal
Heat gained = Mass of x Specific heat of x Change in temperature
by the water water (g) water (4.184 J/goC) (ΔT)

The specific heat of the metal can now be calculated:

Specific heat = Heat gained by the water
of metal (c) Mass of metal (g) x ΔT of metal (oC)

- both b and d.

-since b and d are the closest coastlines then that makes it the most affected.

< 3

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2