2 H2O2 2H2O + O2
V O2 = 63 mL, P=1.008 atm, T=294 K, R=0.0831
amount of 2H2O2 in experiment...
2 H2O2 2H2O + O2
V O2 = 63 mL, P=1.008 atm, T=294 K, R=0.0831
amount of 2H2O2 in experiment was 5mL
1. using ideal gas law, n = PV/RT find moles of O2.
2. Find theoretical moles of O2
3. Using actual moles and theoretical moles calculate the percentage hydrogen peroxide in your experiment.
Answers: 2
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