What will the change in temperature be when 90 J are applied to 15 g of gold. (cgold = 0.126 J/g°C)

47.6°C is the change of temperature

Explanation:

To solve this question we must use the equation of specific heat of a material:

Q = m*ΔT*S

Where Q is heat applied = 90J

m is the mass of the substance = 15g gold

ΔT is change in temperature = Our incognite

S is specific heat of the material = 0.126J/g°C for gold

Replacing:

90J = 15g*ΔT*0.126J/g°C

90J/15g*0.126J/g°C = ΔT

ΔT = 47.6°C is the change of temperature

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml