2Al + 6HBr --> 2A Br3 + 3H2
When 86.94 g of Aluminum reacts with 401.26 g of HBr:
1. What...
2Al + 6HBr --> 2A Br3 + 3H2
When 86.94 g of Aluminum reacts with 401.26 g of HBr:
1. What is the limiting reactant?
2.What is the maximum theoretical amount (in grams) of H2 that can be formed?
3. How much excess reactant is left over after the reaction stops?
4. If a student in a lab performed this experiment and got a 90% Yield of H2, what was the actual yield of H2
Answers: 3
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