Name the following compound
CH 3 – CH 2 – CH = CH – CH 2 – CH 3

hex-3-ene

remember the least number rule and since the double bond lies at 3rd C-atom from either ways, the compound is named hex (six carbon atoms) -3(position of double bond)-ene (primary suffix for unsaturated organic compound where any two carbons have double bond). hex-3-ene.

if you have any doubt, please feel free to ask :-))

true

explanation:

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%