A sample of gas at 90 degrees Celsius occupies 15.5 L. This gas is heated to occupy a new volume of 20.3L. What is the new temperature of the gas?

202 °C

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 90 °C

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

Next, we shall convert 90 °C to Kelvin temperature. This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T₁) = 90 °C

Initial temperature (T₁) = 90 °C + 273

Initial temperature (T₁) = 363 K

Next, we shall determine the final temperature.

Initial temperature (T₁) = 363 K

Initial volume (V₁) = 15.5 L

Final volume (V₂) = 20.3 L

Final temperature (T₂) =?

V₁ / T₁ = V₂ / T₂

15.5 / 363 = 20.3 / T₂

Cross multiply

15.5 × T₂ = 363 × 20.3

15.5 × T₂ = 7368.9

Divide both side by 15.5

T₂ = 7368.9 / 15.5

T₂ ≈ 475 K

Finally, we shall convert 475 K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T₂ = 475 – 273

T₂ = 202 °C

Thus, the new temperature of the gas is 202 °C

your answers are a,b,,e and f

i hope this

6.4 cm (max) - 25 cm (min)