Chemistry, 12.05.2021 23:50 brittanysanders
CuCl2 + 2 NaNO3 → Cu(NO3)2 + 2 NaCl
1) If 1.56 moles of copper (II) chloride, CuCl2 react with 2.02 moles of sodium nitrate, NaNO3, how
many moles of sodium chloride, NaCl, can be formed? What are the limiting and excess
reactants? How many grams of the excess reactant remain when the reaction stops? If 1.26
moles of sodium chloride are actually produced, what is the percent yield of sodium chloride?
Answers: 1
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CuCl2 + 2 NaNO3 → Cu(NO3)2 + 2 NaCl
1) If 1.56 moles of copper (II) chloride, CuCl2 react with 2.02...
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