Um dos mais importantes usos da amônia é como reagente na primeira etapa da rota sintética para produção de ácido nítrico. Essa primeira etapa, não balanceada, ocorre de acordo com a equação NH3(g) + O2(g) <--> NO(g) + H2O(g). A expressão para a constante de equilíbrio dessa reação é: Escolha uma: a. Keq = ([NO]4[H2O]6) / ([NH3]4[O2]5). b. Keq = ([NO]2[H2O]3) / ([NH3]2[O2]5). c. Keq = ([NH3][O2]) / ([NO][H2O]). d. Keq = ([NH3]4[O2]5) / ([NO]4[H2O]6). e. Keq = ([NO]4) / ([NH3]4[O2]5).

The answer is nitrogen-containing bases

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.