4. A typical human consumes 2500 Kcal of energy during a day. This is the equivalent to 10,450,000 J. Say you decided to run stairs all day. Given that there are: 24 hours / day • 60 minutes / hour • 60 seconds / minute = 86,400 seconds / day How much energy, in Joules, would you burn in climbing stairs all day?

The amount of energy that would be burnt in climbing stairs all day is approximately 52,738,560 Joules

Explanation:

The question is with regards to an experiment with details that can be obtained from the U Oregon website

The given parameters of the question are;

The energy consumed by a human each day =  2,500 kcal = 10,450,000 J

The required parameters obtained from U Oregon website are;

The average weight of a student, W ≈ 60 kg × 9.81 m/s² = 588.6 N

The average time it takes a student to run up a flight of stairs = 5.4 s

The height of the stairs, h = 0.2 m × 28 = 5.6 meters

Therefore, we get;

Work done in climbing up the stares = W × h = 588.6 N × 5.6 meters = 3,296.16 J

The height the student can climb in a day is given as follows;

The time of 1 day in seconds, t = 86,400 s

The height the student climbs in 5.4 s = 5.6 m

∴ Vertical velocity, = 5.6 m/(5.4 s) = (28/27) m/s

The vertical height the student climbs in a day, = × t

∴ = (28/27) m/s × 86,400 = 89,600 m

The work done all day = W × = 588.6 N × 89,600 m = 52,738,560 J

The amount of energy in joules that would be burnt in climbing stairs all day = The work done all day = 52,738,560 Joules

the answer would be a

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