How much potassium chloride is needed to make 0.500 m solution with 1.50 L of water?

55.9 g KCl.

Explanation:

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In this case, according to the definition of molality for the 0.500-molar solution, we need to divide the moles of solute (potassium chloride) over the kilograms of solvent as shown below:

Thus, solving for the moles of solute, we obtain:

Since the density of water is 1 kg/L, we obtain the following moles:

Next, since the molar mass of KCl is 74.5513 g/mol, the mass would be:

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