2 C6H14 + 19 O2 --> 12 CO2 + 14 H2O Given 250 g of Oxygen and 50 grams of CoH14 what is the maximum amount of water that can be formed?
• Box 1 = number
• Box 2 = units
Box 3 = Substance​

4.06 mol H₂O

Explanation:

First we convert the given masses of reactants into moles, using their respective molar masses:

Now we calculate how many O₂ moles would react completely with 0.58 C₆H₁₄ moles, using the stoichiometric coefficients of the reaction:

As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that C₆H₁₄ is the limiting reactant.

Now we can calculate how much water can be formed, using the number of moles of the limiting reactant:

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a

catya your not at all which answer i've seen you do this on another question!