A gas occupies 4.21 Iiters at a pressure 1 074 atm. What will its volume be if the pressure is decreased to 0.46 atm?

15.9 Liters

Explanation:

according to Boyle's law P1V1 = P2V2

so we just plug in the values the problem gives us and solve for V2

(1.74)(4.21)=(.46)(V2)

V2 = 15.9 Liters

*note - there is a typo in your question when you states P1 = 1 074 atm. I just assumed you meant 1.74, if this is a mistake just replace 1.74 with the real P1 and solve it as shown above

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