Consider the unbalanced equation for the neutralization of acetic acid: αHC2H3O2(aq)+βBa(OH)2(aq) →γH2O(l)+δBa(C2H3O2)2(aq)
1- Balance the equation.
Give your answer as an ordered set of numbers α, β, γ, ... Use the least possible integers for the coefficients.
2-Determine how many moles of Ba(OH)2 are required to completely neutralize 0.442 mole of HC2H3O2.

Now

This looks hard to balance because the elements are highly distributed

The step to take is

Write out the Number of atoms of each element on the reactant side and those on the product side

Balance the (CH3COO)Ba on the product side by putting 2 I'm front of acetic acid on tbe reactant side.

Then balance Oxygen and Hydrogen by putting 2 in front of H2O

The balance reaction will be

2HC2H3O2 + Ba(OH)2 ==2H2O + Ba(C2H3O2)

Now for the last part

How many Moles of Ba(OH)2 that'll neutralize 0.442moles of Acetic acid

From the balanced equation

2 moles of acetic acid(HC2H3O2) reacts with 1mole of Ba(OH)2

Therefore

The ratio is 2:1

So 0.442 moles of acetic acid will react with 0.442/2 moles of Ba(OH)2

= 0.221moles of Ba(OH)2.

Explanation