IF 3.25 mol of argon gas occupies a volume of 100. L at a particular temperature and pressure, wihat volume does 14.15 moi of argon occupy under the same conditions?

435.38 L

Explanation:

From the question given above, the following data were obtained:

Initial mole (n₁) = 3.25 mole

Initial volume (V₁) = 100 L

Final mole (n₂) = 14.15 mole

Final volume (V₂) =?

The final volume occupied by the gas can be obtained as follow:

V₁/n₁ = V₂/n₂

100 / 3.25 = V₂ / 14.15

Cross multiply

3.25 × V₂ = 100 × 14.15

3.25 × V₂ = 1415

Divide both side by 3.25

V₂ = 1415 / 3.25

V₂ = 435.38 L

Thus, the final volume of the gas is 435.38 L

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