2. If I have 7.70 moles of gas at a pressure of 202.6 kPa, and a temperature of 59.0°C, what is the volume of the container that the gas is in?

V = 0.104 m³

Explanation:

Given that,

Number of moles, n = 7.70 moles

Pressure, P = 202.6 kPa

Temperature, T = 59.0°C = 332 K

We need to find the volume of the container that the gas. We know that the ideal gas law is as follows :

, R =8.314 m³-Pa/K-mol

Put all the values,

So, the volume of the container is equal to 0.104 m³.

a 20-cm-long, cylindrical graphite (pure carbon) rod is inserted into an oxidizing atmosphere at 1145 k and 1.013 x 105 pa pressure. the oxidizing process is limited by the diffu- sion of oxygen counterflow to the carbon monoxide that is formed on the cylindrical surface.

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