In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is. a) reduced, and the oxidation number changes from +1 to 0.
b)reduces and the oxidation number changes from +2 to 0.
c)oxidized and the oxidation number changes from 0 to +1.
d) oxidized, and the oxidation number changes from +1 to 0.
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0.2348 grams of pbcl2 used to form 44.0 ml of solution.

The scheme below is from a series of reactions that are part of a synthesis of vitamin a. answer the following questions with reference to this scheme. (i) what is "reagent a"? (ii) draw a step-by-step mechanism which explains the formation of compound c from compound b (iii) which reagents would you use to form compound e from compounds c and d (reagents b and c)? for each reagent suggested above in (ii) explain the role of the reagent in the reaction to (iv) form compound e. you may wish to do this by drawing a mechanism. 1. addition of reagent a но reagent a 2. н,о" thо oh нон-с compound a. compound b. compound c .ch-оh 1. reagent b "сно 2. reagent c сh oh compound e. compound d.

Use the periodic table to complete this equation that represents nuclear fission processesun - ba c 3 n