What is the change in energy of a gas at a pressure of 105 kPa, if 245 J of energy is added causing a change in volume from 25.3 L to 38.6 L?

-1151.5 J

Explanation:

Given that:

The supplies energy = 245 L

The energy used in the expansion of gas = Pressure ×ΔV (change in volume)

At standard conditions;

Pressure = 105 × 10³ Pa

energy used in the expansion = 105 × 10³ Pa × (38.6 - 25.3)L

= 1396.5 J

Thus, the change in the energy of gas = 245 - 1396.5 J

= -1151.5 J

Hence, we can conclude that the gas has lost its own energy in the process of expansion.

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.

in the analysis of systems that involve fluid flow, we frequently encounter the combination of properties u and pv.