How many liters of a 18.0M stock solution of NaCl are needed to make 2.0L of a 2.5M solution? Your
•54L
•28L
•22.5L
•14.4L

0.28 L

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 18 M

Volume of diluted solution (V₂) = 2 L

Molarity of diluted solution (M₂) = 2.5 M

Volume of stock solution needed (V₁) =?

The volume of the stock solution needed can be obtained as follow:

M₁V₁ = M₂V₂

18 × V₁ = 2.5 × 2

18 × V₁ = 5

Divide both side by 18

V₁ = 5 / 18

V₁ = 0.28 L

Thus, the volume of the stock solution needed is 0.28 L

1. a)c-14 has two more protons

2. d)they have different numbers of protons, neutrons, and valence electrons; they are all gases at room temperature.

3. c) iron and nickel.

the answer is a! (2.9 x 10^-18 j) hope i could someone. : )