What is the value of delta G at 292 for a reaction in which deltaH = 92 kj/mol and delta S= 2.38 kj/mol K

The value of is -602.96 kJ/mol at 292 k for a reaction in which = 92 kj/mol and = 2.38 kj/mol K.

Explanation:

Given: Temperature = 292 K

= 92 kJ/mol

= 2.38 kJ/mol

Formula used to calculate the value of is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the value of is -602.96 kJ/mol at 292 k for a reaction in which = 92 kj/mol and = 2.38 kj/mol K.

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answer; 4 electrons;