413 mg of dried KHP is dissolved in 41 mL of distilled water and titrated with potassium hydroxide (KOH). If it took 20.05 mL of KOH to reach the endpoint, determine the concentration of KOH. Show calculations.

The concentration of KOH is 0.1 M.

Explanation:

Given: Mass of KHP = 413 mg (1 mg = 0.001 g) = 0.413 g

Volume of KOH = 20.05 mL

Volume of solution = 41 mL

The molecular mass of KHP is 204.22 g/mol

Hence, moles of KHP are calculated as follows.

As molarity is the number of moles of a substance present in a liter of solution.

So, molarity of the given solution is as follows.

When the given solution is titrated with KOH then concentration of KOH is calculated as follows.

Substitute the values into above formula.

Thus, we can conclude that the concentration of KOH is 0.1 M.

the correct answer is a

the number of valence electrons for each molecule or ion is shown beneath the structure. remember hydrogen will not have more than two electrons. this hydrogen is part of a covalent bond (sharing two electrons). a double bond here would cause hydrogen to share four electrons with phosphorus.