What is the limiting reactant if you reacted 20.00 g of MgF(2) with 20.00 g of Li If this helps :

These are the molar masses for each :

MgF(2) = 62.3g/mol
Li = 6.9g/mol
Mg = 24.3g/mol
LiF = 25.9g/mol

Main question :

MgF(2) + 2 Li —> Mg + 2 LiF

the answer is 0.42 is that is an option. this question provides no info

ca has a crystalline lattice with positive ions (since it is a metal, metals are positively charged) and electrons flow freely in its structure since the ca atoms have a large nuclear radius so the electrons are not tightly held, therefore the electrons can flow freely since they are not being highly attracted by the nucleus. moreover, one of the properties of metals are that they are conductors of electricity, thus proving ca is the element.