subject
Chemistry, 18.05.2021 20:00 asmaamasto

This is for Science can someone at least draw a picture and post it so I save it please?


This is for Science can someone at least draw a picture and post it so I save it please?

ansver
Answers: 3

Another question on Chemistry

question
Chemistry, 22.06.2019 01:30
100 points answer quick the table compares the number of electrons in two unknown neutral atoms. comparison of electrons atom number of electrons a 10 d 11 use this information to determine the number of valence electrons in the atoms. which of the following correctly compares the stability of the two atoms? both are unreactive. both are highly reactive. a is unreactive and d is reactive. a is reactive and d is unreactive.
Answers: 1
question
Chemistry, 22.06.2019 02:50
The conventional equilibrium constant expression (kc) for the system below is: 2icl(s) ⇄ i2(s) + cl2(g) [cl2] ([i2] + [cl2])/2[icl] [i2][cl2]/[icl]2 none of the listed answers are correct [i2][cl2]/2[icl]
Answers: 2
question
Chemistry, 22.06.2019 03:40
Kc = 0.040 for the system below at 450oc. if a reaction is initiated with 0.40 mole of cl2 and 0.40 mole of pcl3 in a 2.0 liter container, what is the equilibrium concentration of cl2 in the same system? pcl5(g) ⇄ pcl3(g) + cl2(g)
Answers: 3
question
Chemistry, 22.06.2019 20:00
Phosphoric acid is a triprotic acid ( =6.9×10−3 , =6.2×10−8 , and =4.8×10−13 ). to find the ph of a buffer composed of h2po−4(aq) and hpo2−4(aq) , which p value should be used in the henderson–hasselbalch equation? p k a1 = 2.16 p k a2 = 7.21 p k a3 = 12.32 calculate the ph of a buffer solution obtained by dissolving 18.0 18.0 g of kh2po4(s) kh 2 po 4 ( s ) and 33.0 33.0 g of na2hpo4(s) na 2 hpo 4 ( s ) in water and then diluting to 1.00 l.
Answers: 3
You know the right answer?
This is for Science can someone at least draw a picture and post it so I save it please?
...
Questions
question
Mathematics, 11.09.2021 04:10
question
Mathematics, 11.09.2021 04:10
question
Mathematics, 11.09.2021 04:10
Questions on the website: 13722360