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436.8 mmHg.

Explanation:

From the question given above, the following data were obtained:

Total pressure (Pₜ) = 0.93 atm

Pressure of N₂ (Pₙ₂) = 270 mmHg

Pressure of O₂ (Pₒ₂) =?

Next, we shall convert the total pressure to mmHg . This can be obtained as follow:

1 atm = 760 mmHg

Therefore,

0.93 atm = 0.93 × 760 mmHg / 1 atm

0.93 atm = 706.8 mmHg

Finally, we shall determine the pressure of the O₂. This can be obtained as follow:

Total pressure (Pₜ) = 706.8 mmHg

Pressure of N₂ (Pₙ₂) = 270 mmHg

Pressure of O₂ (Pₒ₂) =?

Pₜ = Pₙ₂ + Pₒ₂

706.8 = 270 + Pₒ₂

Collect like terms

706.8 – 270 = Pₒ₂

436.8 = Pₒ₂

Pₒ₂ = 436.8 mmHg

Thus, the pressure of O₂ is 436.8 mmHg

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answer: a tank of height h is filled with water and sits on the ground. water squirts from a hole at a height y above the ground and has a range r. for two y values, 0 and h, r is zero. determine the value of y for which the range will be a maximum.

explanation: