A hot metal plate at 150°C has been placed in air at room temperature. Which event would most likely take place over the next few minutes?

O Molecules in both the metal and the surrounding air will start moving at lower speeds.

O Molecules in both the metal and the surrounding air will start moving at higher speeds.

O The air molecules that are surrounding the metal will slow down, and the molecules in the metal will speed up.

O The air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down.

The event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.

Explanation:

A process in which heat is evolved is called an exothermic process.

When hot metal plate at is placed in air at room temperature then heat is given off by the metal plate due to which there will occur a decrease in kinetic energy of its molecules.

As a result, molecules in the metal will slow down.

Whereas heat is absorbed by the air molecules from the metal due to which kinetic energy of air molecules will increase.

Thus, we can conclude that the event air molecules that are surrounding the metal will speed up, and the molecules in the metal will slow down would most likely take place over the next few minutes.

explanation: no but i do not usually comment

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :