What is the pressure of gas at 496 Liters and 200 Kelvin if the original pressure was 0.250 atm. at 300 liters and 400 kelvin?

0.076 atm

Explanation:

Using the combined gas law formula;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

T1 = initial temperature (K)

T2 = final temperature (K)

V1 = initial volume (L)

V2 = final volume (L)

According to the information provided in this question;

P2 = ?

P1 = 0.250 atm

V2 = 496 L

V1 = 300 L

T2 = 200K

T1 = 400K

Using P1V1/T1 = P2V2/T2

0.250 × 300/400 = P2 × 496/200

75/400 = 496 P2/200

0.1875 = 2.48P2

P2 = 0.1875 ÷ 2.48

P2 = 0.076 atm

1. for the first question, we must find the mass of the anhydrous salt, mgso₄. the molar mass for mgso₄·7h₂o is 246.47 g/mol, while that of mgso₄ is 120.37 g/mol.7.834 g mgso₄·7h₂o * 1 mol mgso₄·7h₂o/246.47 g * 1 mol mgso₄/1 mol mgso₄·7h₂o * 20.37 g mgso₄/mol = 0.647 g mgso₄

2. mass of water = mass of sample - mass of anhydrous salemass of water = 7.834 - 0.647 = 7.19 gpercent water in hydrate = 7.19/7.834 * 100 = 91.74%