Chemistry, 20.05.2021 18:40 soloriorafa
I. A student calculated the molarity of a solution prepared by dissolving 0.730 mol of table sugar (sucrose, C12H22O11) in 1.8x10^3 mL of water as 4.06x10^-4 M C12H22O11. Explain the student's calculation error and explain how the student should solve for the correct value of molarity. Show a valid calculation for the molarity.
Answers: 2
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Asample of ammonia reacts with oxygen as shown. 4nh3(g) + 5o2(g) 4no(g) + 6h2o(g) what is the limiting reactant if 4.0 g of nh3 react with 8.0 g of oxygen? o2 because it produces only 0.20 mol of no. nh3 because it produces only 0.20 mol of no. o2 because it produces two times less no than nh3. nh3 because it produces three times more no than o2.
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I. A student calculated the molarity of a solution prepared by dissolving 0.730 mol of table sugar (...
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