3CaCl2 + 2AlF3 --> 3CaF2 + 2AlCl3 How many moles of CaF2 will form from 36 moles of AlF3?

54 moles

Explanation:

The ratio of AIF3 to CaF2 is, as seen in the equation, 2:3. This means you multiply 36 moles by 3, and then divide it by 2. This equals 54 moles of CaF2.

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

the density(ratio between mass and volume as m/v) decreases from top to bottom in periodic table group as the size increases and nuclear charge decreases. but in periods density increases from left to right as atom size decreases and nuclear charge increases.