Ni2+ (aq) + Ca(s) → Ni(s) + Cd2+ (aq) E = +0.15 V Under standard conditions, a Ni-Cd galvanic cell generates a potential of +0.15 V using the chemical reaction represented above. Which of the following best explains how [Ni²+1>1 M affects the cell potential if this is the only change made to the operation of the galvanic cell? A The ratio Cd2+] Ni?+1 is smaller if (Ni2] >1 M, resulting in Q < 1 and Ecell > Ecell B Cd²+] The ratio is smaller if (Ni2+] > 1 M, resulting in Q >1 and Ecell > Ecell [Ni] С The ratio [Ni2+1 [Cd²+1 is larger if [Ni2+] > 1 M, resulting in Q >1 and Ecel 1 M, resulting in Q <1 and Ecell < Ecell- Cd +1