Find the kinetic energy of a boy of mass 6.5kg running at a velocity of 6.0m/s​

Explanation:

Given,

M=6.5kg,velocity(v)=6m/s

K.E=1/2mv^2

=1/2×6.5×6^2

=1/2×6.5×36

=18×6.5

=117 J

h let me think

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.