If you want to make 8.00 moles of AlF₃ how many moles of F₂ will you need, using the following balanced chemical equation? 2 Al + 3 F₂ → 2 AlF₃

You will need 12.0 moles of F₂

Explanation:

Based on the chemical equation, 2 moles of AlF₃ are produced when 3 moles of F₂ are added in an excess of Al.

Using this expression: 2mol AlF₃ = 3mol F₂ we can find the moles of F₂ as follows:

8.00 mol AlF₃ * (3mol F₂ / 2mol AlF₃) =

You will need 12.0 moles of F₂

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